Hi All,
Iam new to the DataStage,I need a help on 'Make Vector' stage.
Basically it'll converts rows to columns.
Till now we written a query in DB2 stage to convert rows to
columns. But client asking to use a stage instead of writing a huge
query.
But evey one saying to use Pivot stage.It's not helpful
Can any one pls help ASP
Thanks,
jayakrishna
Need help on 'Make Vector' Stage
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jayakrishna.koganti
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Need help on 'Make Vector' Stage
Last edited by jayakrishna.koganti on Mon Apr 21, 2008 10:29 pm, edited 2 times in total.
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ray.wurlod
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Welcome aboard.
As a matter of principle we resent "ASP" requests. DSXchange is an all-volunteer site whose participants post as and when they can. If you want urgent help, sign up with your support provider for premium service, and learn that there is a true cost associated with "urgent".
A vector is not multiple columns, a vector is contained in one column, so a Make Vector stage is probably not the solution you require.
You need to be more specific about your requirement in order to make a sensible choice of stage type. Meanwhile, having read the chapter in the Parallel Job Developer's Guide on the Make Vector stage, what is it from that that you don't understand?
As a matter of principle we resent "ASP" requests. DSXchange is an all-volunteer site whose participants post as and when they can. If you want urgent help, sign up with your support provider for premium service, and learn that there is a true cost associated with "urgent".
A vector is not multiple columns, a vector is contained in one column, so a Make Vector stage is probably not the solution you require.
You need to be more specific about your requirement in order to make a sensible choice of stage type. Meanwhile, having read the chapter in the Parallel Job Developer's Guide on the Make Vector stage, what is it from that that you don't understand?
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Any contribution to this forum is my own opinion and does not necessarily reflect any position that IBM may hold.
Any contribution to this forum is my own opinion and does not necessarily reflect any position that IBM may hold.