finding the space character

[DSguru2B]

Nothing out of the box but you can use the LEFT() function.

Code: Select all

if LEFT(in.Link, 1) = " " then 'Space present' else 'No space'

[ray.wurlod]

Do you need to find it? Trimming leading space characters works just as effectively if there are some and if there are none. You could always compare the trimmed version with the original, perhaps in stage variables, then use the trimmed version as you wish.