How could I get current parameter value from unix command

meesolo · Post by **meesolo** » Tue Sep 11, 2007 10:56 am

How could I get current parameter value from unix command? I tried to use dsjob -paraminfo but it returned only default value.

Thanks in advance

chulett · Post by **chulett** » Tue Sep 11, 2007 12:03 pm

By 'current' parameter value, you mean what? The value actually used the last time the job was run? Technically, the default value is the 'current' value.

meesolo · Post by **meesolo** » Tue Sep 11, 2007 12:09 pm

Yes, I would like get last run parameter value.

chulett · Post by **chulett** » Tue Sep 11, 2007 12:14 pm

You would need to pull that information from the first (Starting Job) entry in the job's log.

meesolo · Post by **meesolo** » Tue Sep 11, 2007 9:07 pm

How could I pull the information from the first entry in job log?

ray.wurlod · Post by **ray.wurlod** » Wed Sep 12, 2007 12:48 am

dsjob -logsum project job
Find and parse out the entry relating to the most recent job start. You can get the job start timestamp from dsjob -jobinfo project job

meesolo · Post by **meesolo** » Wed Sep 12, 2007 12:59 am

I got it. Thank you ray and chulett

ray.wurlod · Post by **ray.wurlod** » Wed Sep 12, 2007 6:02 am

In that case please mark the thread as Resolved.

meesolo · Post by **meesolo** » Thu Sep 13, 2007 6:27 am

I have got another problem. the job start timestamp from dsjob -jobinfo sometimes doesn't match the timestamp in dsjob -logsum .

For Example;

From dsjob -jobinfo command
Job Start Time : Tue Sep 11 17:44:432007

but, from dsjob -logsum command
5 STARTED Tue Sep 11 17:44:44 2007
Starting Job XXXX. (...)

Therefore, I cannot get the log detail

ray.wurlod · Post by **ray.wurlod** » Thu Sep 13, 2007 2:42 pm

Of course you can. The value from -jobinfo is only where -logsum starts; specify a later end timestamp with -logsum, then parse off the first entry.